
Brian R.
asked 05/09/21How do you solve this?
Evaluate the line integral:
∫c xzds where c is the line from (0,1, -1) and (2,0,1)
I started by solving for my r(t) which I found to be <2t, 1-t, -1> and 0 ≤ t ≤ 1. However, when I started plugging in my values for x(t), y(t), and ds, I ended up with the following
∫(2t)(-1)(√5)dt
I got an answer different from what my professor submitted (ultimately being 1)
1 Expert Answer
Richard P. answered 05/10/21
PhD in Physics with 10+ years tutoring experience in STEM subjects
I agree with your professor. The answer should be 1.
I think that your mistake is that r(t) should be < 2t ,1-t , -1 + 2t > , not what you wrote.
With that the length of the line segment is 3 not sqrt(5)
Brian R.
When I did my calculation, I wrote -1 instead of 1 and that throws it all off. My process was right, but that pesky negative sign threw it off. Thank you sir.05/10/21
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Esther G.
05/10/21