Brian R.

asked • 05/09/21

How do you solve this?

Evaluate the line integral:


c xzds where c is the line from (0,1, -1) and (2,0,1)


I started by solving for my r(t) which I found to be <2t, 1-t, -1> and 0 ≤ t ≤ 1. However, when I started plugging in my values for x(t), y(t), and ds, I ended up with the following


∫(2t)(-1)(√5)dt


I got an answer different from what my professor submitted (ultimately being 1)

Esther G.

tutor
Hi Brian! I think that you possibly are on the right track, but made some slight errors in figuring out what r(t) is (or possibly just a typo in writing it here). If you plug in t = 1 into your current expression, you would get (2, 0, -1), not (2, 0, 1). z is not constant in this problem!
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05/10/21

1 Expert Answer

By:

Brian R.

When I did my calculation, I wrote -1 instead of 1 and that throws it all off. My process was right, but that pesky negative sign threw it off. Thank you sir.
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05/10/21

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