Bradford T. answered 05/08/21
Retired Engineer / Upper level math instructor
Doing the implicit derivation
2xy2 + 2x2yy' + y'sin x + ycos x = 0
y'(2x2y + sin x) = -2xy2-ycos x
y' = (-2xy2-ycos x)/(2x2y+sin x) ≠ (2xy2+ycos x)/(2x2y-sin x)
False
School K.
asked 05/08/21the function given were differentiated implicitly. Determine whether the indicated derivative for the function is true or false.
Bradford T. answered 05/08/21
Retired Engineer / Upper level math instructor
Doing the implicit derivation
2xy2 + 2x2yy' + y'sin x + ycos x = 0
y'(2x2y + sin x) = -2xy2-ycos x
y' = (-2xy2-ycos x)/(2x2y+sin x) ≠ (2xy2+ycos x)/(2x2y-sin x)
False
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