Tom K. answered 05/07/21
Knowledgeable and Friendly Math and Statistics Tutor
If the asymptote is 12, k = 12
y = ab^x + 12
We have (2, 264) and (6, 4044).
Thus,
264 = ab^2 + 12
4044 = ab^6 + 12
252 = ab^2
4032 = ab^6
Divide the second equation by the first
16 = b^4
b = 16^(1/4) = 2^4^(1/4) = 2^1 = 2
Then, ab^2 = 252
4a = 252
a = 63
y = 63 * 2^x + 12