For y=x2 Newtown's method becomes xn+1=(1/2)[xn+(N/xn] where N is the number of which you want the square root.
Start with x0=5 and in 3 or 4 iterations you will have your answer.
Maggie D.
asked 05/07/21For y=x2 Newtown's method becomes xn+1=(1/2)[xn+(N/xn] where N is the number of which you want the square root.
Start with x0=5 and in 3 or 4 iterations you will have your answer.
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