the equation of a line that passes through the point (0,9) and is perpendicular to y-3 = (1)/(3) (x +2) can be expressed in the form y= ax +b

Question

y-3 = 1 (x +2)

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3

Answer 1

From the perpendicular requirement we obtain that the slope of the requested line must be -3. Since we want our line to pass through the point (0,9) we have the equation 9=0+B or B=9. So the line will have the equation y=(-3)x+9.