A ball is thrown straight upward so that its height (in feet) at time t seconds is given by the function h(t)=−16t^2+60t+92.

Question

what is the average velocity of the ball between 0 and 2 seconds?

what is the instantaneous velocity of the ball at 4 seconds?

Answer 1

Average Velocity given the position function is the average rate of change of the position function. PLug the following values into the given position function, h(t).

[h(2) - h(0)]/(2-0)

Instantaneous Velocity is the rate of change of position at a particular instant --> the derivative at that point!

h ' (4) = v (4)

Find h ' (t) and plug in t = 4!