Kurt C. answered 05/05/21
Math, Science & Computer tutor
Differentiating both sides of the equation and using the product rule for the first term gives
3( 1 * y + y' * x) - 2x = 0
3(y + xy') = 2x
y + xy' = (2/3)x
xy' = (2/3)x - y
y' = (2/3) -y/x
If we solve for y using the original equation and substitute above, we can get y' in terms of x.
y = x/3 + (4/3x)
y' = 1/3 - 4/(3x2)
