Inactive Tutor answered 02/18/26
n(720, 50)
a) 50%
b) p(x>850)= 100- 99.5%= 1/2 % chance
z= (850-720)/50=13/5=2.6
c) p(620<x<770) z =1 and - 2
corresponding areas, with the empircal rule are .34 and .475
add them = .825 = 82 1/2 %
Kibiie L.
asked 05/04/21According to the data released by the Chamber of Commerce of a certain city, the weekly wages of factory workers are normally distributed with a mean of $720 and standard deviation of $50. Find the probability that a worker selected at random from the city makes the following weekly wage. (Round your answers to four decimal places.)
(a) less than $720
(b) more than $845
(c) between $620 and $770
Inactive Tutor answered 02/18/26
n(720, 50)
a) 50%
b) p(x>850)= 100- 99.5%= 1/2 % chance
z= (850-720)/50=13/5=2.6
c) p(620<x<770) z =1 and - 2
corresponding areas, with the empircal rule are .34 and .475
add them = .825 = 82 1/2 %
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