Question asked below

Question

What is the probability you pull an Ace from a standard deck of cards given that 12 cards have already been pulled and 3 of them are aces?

Answer 1

Let me show you a simple explanation:

A = an ace

B= 12 random cards

There are 52 cards in a deck. 12 cards have been pulled out.

P(B) = 12/52

The probability of pulling a card aside from the 12 that have been pulled out.

P(B') = 40/52

However, 3 of those 12 cards are aces. That's already been given. So the probability of getting an ace from those 12 cards is:

P(A|B) = 3/12

There are 4 aces in a deck. That means there is one more ace left in the remaining 40 cards.

P(A|B') = 1/40