Inactive Tutor answered 05/02/21
(x+1)^2(x^2+16)=
(x^2+2x+1)(x^2+16)=
x^4 + 2x^3 + 17x^2 + 32x +16 is a 4th degree polynomial with zeros 4i,-4i and -1
set each factor = 0
x+1 = 0
x=-1
x^2+16 = 0
x^2 =-16
x =4i or -4i
Josie G.
asked 05/02/21Find a fourth-degree polynomial with integer coefficients that has zeros 4i and −1, with −1 a zero of multiplicity 2.
Inactive Tutor answered 05/02/21
(x+1)^2(x^2+16)=
(x^2+2x+1)(x^2+16)=
x^4 + 2x^3 + 17x^2 + 32x +16 is a 4th degree polynomial with zeros 4i,-4i and -1
set each factor = 0
x+1 = 0
x=-1
x^2+16 = 0
x^2 =-16
x =4i or -4i
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