U is not a subspace of R3 because U is not closed under scalar multiplication.
For example, v = <1/2, 0,0 > is in U but 3v = <3/2, 0, 0> is not.
Cj C.
asked 04/29/21Determine whether or not the set of vectors identified is a subspace of:
#1.
R3 if U={vectors whose length does not exceed 1} , i.e., U= {(a, b, c): a² + b² + c² ≤1}
U is not a subspace of R3 because U is not closed under scalar multiplication.
For example, v = <1/2, 0,0 > is in U but 3v = <3/2, 0, 0> is not.
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