Inactive Tutor answered 04/29/21
Solution:
The subset W = { (x,y,1) | x, y ∈ R} is not closed under the addition because if we take u = (1,1,1) and v = (0,0,1), then u ∈ W and v ∈ W, but u + v = (1,1,2) ∉ W. Therefore, W is not a subspace of R^3.
Cj C.
asked 04/29/21Determine whether or not the set of vectors identified is a subspace of:
#1.
R3 if W is the set of all vectors of the form (x, y, 1) under the usual vector addition and scalar multiplication.
Inactive Tutor answered 04/29/21
Solution:
The subset W = { (x,y,1) | x, y ∈ R} is not closed under the addition because if we take u = (1,1,1) and v = (0,0,1), then u ∈ W and v ∈ W, but u + v = (1,1,2) ∉ W. Therefore, W is not a subspace of R^3.
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