Brian P.

asked • 04/27/21

Write equations of cosine functions using properties

Find an equation for a sinusoidal function that has period 2​𝜋, amplitude 1, and contains the point (𝜋,4)


Cos


2pi/2pi=1


Cos(x)


4 = Cos(pi+C)+D


4= Cos (pi+0) +D


4= Cos (pi)+D


4= (-1) +D My misunderstanding is how to arrive at -1 ???


5= D


Cos(x)+5


.



1 Expert Answer

By:

Brian P.

Thanks so much, I had been struggling for days and this really made sense. But what if.... Period = 540 degrees.....A=1.....on the point (-405 degrees, 5).....cos (2/3x)(This makes sense).......5=cos(-270 degrees)+D.....where does the -270 come from??? And how do I know that equals 0?
Report

04/27/21

Mark M.

tutor
x = -405 degrees So, (2/3)x = (2/3)(-405) = -270 degrees.
Report

04/28/21

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