The answer is C.
dy/y2 = dx
-1/y = x + C
You figure it out from here.
La'Kyerah M.
asked 04/27/21Let y= f(x) be the particular solution to the differential equation dy/dx= y2 with the initial condition f(1)= 1. Which of the following gives an expression for f(x) and the domain for which the solution is valid?
A. f(x)= (2x-1)/x for x≠0
B. f(x)= (2x-1)/x for x>0
C. f(x)= 1/(2-x) for x≠2
D. f(x)= 1/(2-x) for x<2
The answer is C.
dy/y2 = dx
-1/y = x + C
You figure it out from here.
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