Daniel B. answered 04/23/21
A retired computer professional to teach math, physics
f(x) = (x+1)3/2 (x−4)5/2 / (5x+3)2/3
(ln(f))(x) = (3/2)ln(x+1) + (5/2)ln(x-4) - (2/3)ln(5x+3)
(ln(f))'(x) = 3/(2(x+1)) + 5/(2(x-4)) - 10/3(5x+3)
The general formula of logarithmic differentiation is
f' = (ln(f))' × f =
(3/(2(x+1)) + 5/(2(x-4)) - 10/(3(5x+3))) (x+1)3/2 (x−4)5/2 / (5x+3)2/3