Tom K. answered 04/23/21
Knowledgeable and Friendly Math and Statistics Tutor
This is 1 - P(both seats available are in the other 6 cars). There are 700 seats, and 600 seats in the other cars.
1 - C(600,2)/C(700,2) = 1 - (600*599)/(700*699) = 433/1631 = .2655
You can also calculate this using 1 - HYPGEOM.DIST(0,100,2,700,0)
Interesting bounds on this probability: it is less than 2/7, as this is the expected number of seats available in the first car. It is greater but very close to 1 - (6/7)^2 = 13/49 = .2653, which is the number we get when having two independent samples.