60/(x2-4) is identically equal to [A/(x+2)]+[B/(x-2)]
Ax-2A+Bx+2B is identically equal to 60
A+B=0 and A=-B
and -2A+2B=60 => B= 15
A=-15
You should be able to answer the question now.
P.S. "Identically" means for every value of x!
Arslan M.
asked • 04/22/21calculus two 2
The partial fraction decomposition of 60/x^2−4 can be written in the form of f(x)/x−2+g(x)/x+2, where
f(x)=
g(x)=
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