Find p(-2) and p(3) for the function.

Question

1.Find p(-2) and p(3) for the function.

p(x)=x^3-x^5

2.Find p(-2) and p(3) for the function.

p(x) = –x⁵ + 4x³

^3.If p(x) = 3x² – 4 and r(x) = 2x² – 5x + 1, find each value.

p(8a)

4.If p(x) = 3x² – 4 and r(x) = 2x² – 5x + 1, find each value.

r(x + 2)

Answer 1

For each of these problems, you will substitute numerical value for x and solve. These problems increase in difficulty. Here are the first 2. Make sure you understand these first, before we move on to the last 2!!

1) p(x) = x³ - x⁵

p(-2) = (-2)³ - (-2)⁵

p(-2) = (-8) - (-32)

p(-2) = (-8) + 32

p (-2) = 24

p(x) = x³ - x⁵

p(3) = (3)³ - (3)⁵

p(3) = 27 - 243

p(3) = -216

2) p(x) = -x⁵ + 4x³

p(-2) = - (-2)⁵ + 4 (-2)³

p(-2) = - (-32) + 4 (-8)

p(-2) = 32 + -32

p(-2) = 0

p(x) = -x⁵ + 4x³

p(3)= - (3)⁵ + 4(3)³

p(3) = - (243) + 4(27)

p(3) = - 243 + 108

p(3) = - 135