Implicit differentiation (remember product rule and any time we differentiate a y term we put a y' after):
3xy2 - 2x3 = 5xy
3(y2 + 2xyy') - 6x2 = 5(y + xy') at (1,2)
3(4 + 4y') - 6 = 5(2 + y')
12 + 12y' - 6 = 10 + 5y'
7y' = 4
y' = 4/7
Sophie M.
asked 04/20/21just want to clarify 3y^(2)x is 3y^2 times x
Implicit differentiation (remember product rule and any time we differentiate a y term we put a y' after):
3xy2 - 2x3 = 5xy
3(y2 + 2xyy') - 6x2 = 5(y + xy') at (1,2)
3(4 + 4y') - 6 = 5(2 + y')
12 + 12y' - 6 = 10 + 5y'
7y' = 4
y' = 4/7
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