Please help thank you in advance

Question

The velocity in ft/sec of a particle is given by v(t) = −14t + 2. Find the position function s(t), of the particle if it has an initial position s(0) = 4 feet.

 7t² + 2t − 4 

−7t² + 2t + 4 

−7t² + 2t − 4 

−14t² + 2t + 4

Answer 1

Integrate v(t) = −14t + 2 to yield the distance

s(t) = -14t²/2 + 2t + C

s(0) = 4

s(t) = -14t²/2 + 2t + 4 = -7t² + 2t + 4