The integral of sin2t should be -0.5 cos(2t).
The travel should be adding the positive part from 0 to pi/2 , and the absolute value of the negative part from pi/2 to pi.
The answer is 2.
Jon B.
asked 04/16/21A particle moves along the x-axis with velocity v(t) = sin(2t), with t measured in seconds and v(t) measured in feet per second. Find the total distance travelled by the particle from t = 0 to t = π seconds.
2
1
1/2
0
The integral of sin2t should be -0.5 cos(2t).
The travel should be adding the positive part from 0 to pi/2 , and the absolute value of the negative part from pi/2 to pi.
The answer is 2.
Inactive Tutor answered 04/16/21
Well total distance travelled = integral of modulus of v(t) from t = 0 to t = π
Integrating modulus of v(t) gives 0.5 cos 2t [ differentiating 0.5 cos 2t gives sin 2t]
When t = π, 0.5 cos 2t = 0.5
When t = 0, 0.5 cos 2t = 0
so distance travelled = 0.5 - 0 = 0.5 ft
Sreeram K.
you said .5 and the other person said 2 so who's right04/29/21
Inactive Tutor
I am correct. Steven has calculated the displacement (this is not the distance). Displacement is a vector , has a size and a distance, and can be positive or negative (relative to where you start). Distance is a scalar, just has a size, and to find it you integrate the modulus (absolute value) of the velocity.04/29/21
Inactive Tutor
Distance has to be positive, displacement can be positive or negative04/29/21
Inactive Tutor
SORRY. Steven has the right answer but his method was slightly inaccurate. sin 2t on the interval is positive, so the absolute value of the velocity is also positive so integrating the absolute value is the same as integrating the actual value. So my method is correct and it should have given 2.04/29/21
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Sreeram K.
you said 2 and the other person said .5 so who's right04/29/21