Bradford T. answered 04/16/21
Tutor
4.9
(29)
Retired Engineer / Upper level math instructor
A = (1/2)∫abr2dθ
A = (1/2)∫02π(1+cos(θ)dθ = (1/2)[θ+sin(θ)]02π
= (1/2)(2π) = π
Bill W.
asked 04/16/21The area of the closed region bounded by the polar graph of r = √(1+cosθ) is...
Bradford T. answered 04/16/21
Retired Engineer / Upper level math instructor
A = (1/2)∫abr2dθ
A = (1/2)∫02π(1+cos(θ)dθ = (1/2)[θ+sin(θ)]02π
= (1/2)(2π) = π
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