Michael M. answered • 04/14/21

Math, Chem, Physics, Test Prep Tutoring with Michael ("800" SAT math)

Let l be the length of the enclosure and w be the width, both in feet. (l and w are interchangeable)

Then we know that

lw = 320.

We're trying to minimize the cost. The two widths we'll say, cost $3 per foot so the cost of both is 3w

The cost of the lengths is $3 per foot for one of them and $14 per foot for the other. So one costs 3l and the other costs 14l

So the cost of the entire enclosure is 3w + 3w + 3l + 14l = 6w + 17l.

Do you think that you can solve the rest?

Madeline H.

So when you get 3w+3w+3l+17l=6w+17l, I added like terms to get 6w+17l=6w+17l which would end up being zero. What would I do to find the dimensions with that equation?04/14/21