Bradford T. answered 04/13/21
Retired Engineer / Upper level math instructor
s(t) = ∫v(t)dt
Estimate with Riemann sums
Δx = (60-0)/6 = 10
L6: ∑f(xi-1)Δx
10[0+10+35+62+79+76] = 10(262) = 2620 ft
R6: ∑f(xi)Δx
10[10+35+62+79+76+56] = 10(318) = 3180 ft
M3: ∑f((xi-1+xi+1)/2))Δx Δx = (60-0)/3 = 20
20[f(10)+f(30)+f(50)] = 20[10+62+76] = 20(148) = 2960 ft