x^2 -6x + 8
take the derivative and set it = 0
2x -6 = 0
2x = 6
x =6/2 =3
3^2 -6(3) + 8 = 9-18+8 = -1 = minimum
absolute & local minimum is (3,-1)
at x=3, the global&local minimum is -1
Jerry N.
asked 04/11/21Find the absolute minimum value on [0, ∞) for f(x)=x^2−6x+8.
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.
A.
The absolute minimum is ________ at x= _______.
B.
There is no absolute minimum.
x^2 -6x + 8
take the derivative and set it = 0
2x -6 = 0
2x = 6
x =6/2 =3
3^2 -6(3) + 8 = 9-18+8 = -1 = minimum
absolute & local minimum is (3,-1)
at x=3, the global&local minimum is -1
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