Tom K. answered 04/11/21
Knowledgeable and Friendly Math and Statistics Tutor
If you do b) first, you have already done a). Of course, a is also easily understood via understanding cross product.
b) pxq = the determinant of
i j k
1 -2 3
2 1 3
=
-9i + 3j + 5k
Then, (pxq) x r = the determinant of
i j k
-9 3 5
1 1 0
=
-5i + 5j - 12k
(p.r)q =(q.r)p =
(1, -2, 3).(1, 1, 0) (2, 1, 3) - (2, 1, 3).(1, 1, 0) (1, -2, 3) =
-(2, 1, 3) -3(1, -2, 3) =
-(2, 1, 3) + (-3, 6, -9) =
(-5, 5, -12)
This equals (pxq) x r above
a) (pxq)xr) = -p -3q (see b)