Mark M. answered 04/08/21
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Use the Ratio Test.
[2n+1 lxl n+1) / (n+1)] ÷ [2n lxl n / n] = 2(n/(n+1)) lxl
Taking the limit as n approaches infinity of the above expression we get 2 lxl.
By the Ratio Test the series converges as long as 2 lxl < 1.
So, lxl < 1/2. This means that -1/2 < x < 1/2
Check the endpoints:
When x = 1/2, we get ∑(1/n) which is the harmonic series (divergent).
When x = -1/2, we have ∑(-1)n/n. This series converges by the Alternating Series Test.
Interval of convergence is -1/2 ≤ x <1/2. (Choice e)