Mark M. answered 9d
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
x = t2 + 2t and y = t3 + t2
When t = 1, x = 3 and y = 2. So, (3,2) is the point of tangency
Slope of tangent = dy/dx evaluated when t = 1.
dy/dx = (dy/dt) / (dx/dt) = (3t2 + 2t) / (2t + 2) = 5/4 (when t = 1)
Equation of tangent line: y - 2 = (5/4)(x - 3)
Simplify to get y = (5/4)x - (7/4)
Aaron J.
That is much easier than expected. Thank you for the help!9d