The antiderivative is 5 tan t - (5/3)t3 + C
You evaluate C using the initial conditon.
Mustafa K.
asked 04/05/21Consider the function f(t)=5sec2(t)−5t2.
Let F(t) be the antiderivative of f(t) with F(0)=0. find f(t)
The antiderivative is 5 tan t - (5/3)t3 + C
You evaluate C using the initial conditon.
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