dy/dx = k/y4
y4dy = kdx
1/5y5 = kx + C
y5 = k1x + C1
y = 5√(k1x + C1). (The subscripts just convey that these 2 are different constants than those in the first equation written after integrating.)
Jeff Q.
asked 04/03/21Write and then solve for y = f(x) the differential equation for the statement: "The rate of change of y with respect to x is inversely proportional to y4."
dy/dx = k/y4
y4dy = kdx
1/5y5 = kx + C
y5 = k1x + C1
y = 5√(k1x + C1). (The subscripts just convey that these 2 are different constants than those in the first equation written after integrating.)
William W. answered 04/03/21
Experienced Tutor and Retired Engineer
Rate of change of y with respect to x is dy/dx. Inversely proportional means that rate = k/y4 so:
dy/dx = k/y4
cross multiplying gives us y4 dy = k dx now integrate both sides:
∫y4 dy = ∫k dx
y5/5 = kx + C or
y5 = C1x + C2
y = 5√(C1x + C2)
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