The normal to the plane is the coefficients of the equation (-1,1,-2) or -i +j -2k in unit vector notation.
Parametric equation is just P + t(normal vector)
The x term of the line is Px + tnx = 2-t
and so on.
Emilyys E.
asked 04/03/21Find the parametric equations for the line through the point P = (2, 4, -5) that is perpendicular to the plane −1𝑥+1𝑦−2𝑧=1.−1x+1y−2z=1.
Use "t" as your variable, t = 0 should correspond to P, and the velocity vector of the line should be the same as the standard normal vector of the plane.
x =
y =
z =
The normal to the plane is the coefficients of the equation (-1,1,-2) or -i +j -2k in unit vector notation.
Parametric equation is just P + t(normal vector)
The x term of the line is Px + tnx = 2-t
and so on.
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