calculussss helppp

Question

) Find the distance from the point (3, 1, -3) to the plane 2𝑥−5𝑦+1𝑧=3

Answer 1

d = |Ax1+By1+Cz1+D| / √(A²+B²+C²)

d = |(3)(2) + (1)(-5) + (-3)(3)| / √(2² + (-5)² + 1²)

d = |6 - 5 - 9| / √(4+25+1)

d = |-8| / √(30)

d = 8/√30

d = 4√30 / 15