
Mark M. answered 04/03/21
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
20000 = p(1 + 0.03/2)2(6)
20000 = p(1 + 0.03/4)4(6)
Kyle B.
asked 04/02/21a) 3%/year compounded semiannually
$_________
b)3%/year compounded quarterly
$__________
Mark M. answered 04/03/21
Mathematics Teacher - NCLB Highly Qualified
20000 = p(1 + 0.03/2)2(6)
20000 = p(1 + 0.03/4)4(6)
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.