Jane A. answered 04/02/21
Experienced Ivy League Math tutor - Patient & Knowledgeable!
- Because f(2) is undefined but f(x) has a limit as x -->2, f(x) has a hole at x = 2. Therefore, both the numerator and denominator have the factor (x - 2)
- Because the limit of f(x) as x --> 2 = 0, there is an additional factor of (x - 2) in the numerator.
- You determine the limit as x approaches the hole after cancelling the factors that cause the hole.
- After these factors are cancelled, there must still be a factor in the numerator that creates this limit when x = 2, i.e. an additional (x - 2) must remain in the numerator after cancelling the factors for the hole.
- Because f(x) goes to +- infinity on either side of x = -3, there must be a factor of (x + 3) in the denominator to create this vertical asymptote.
- So far we f(x) = a (x - 2)2 / (( x + 3)(x - 2))
- By putting in a test value of x = -4 and x = -2, you can find that "a" must be negative so that the function goes to negative infinity as x -->-3- and goes to positive infinity as x --> -3+
Final answer: f(x) = -(x - 2)2 / (( x + 3)(x - 2))