This is a straight integration problem.
The Antiderivative is t2-5t and evaluated between 1 and x is #C
Ssierra K.
asked • 04/02/21Functions Defined by Integrals Help
Use the graph of f(t) = 2t - 5 on the interval [-2, 10] to write the function F(x), where 
A) F(x) = 2x - 5
B) F(x) = x2 - 5x - 4
C) F(x) = x2 - 5x + 4
D) F(x) = x2 - 5x + 36
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