
Patrick B. answered 04/02/21
Math and computer tutor/teacher
I am assuming you want to find the extrema of x^2 * y^2
x^2 * y^2 = x^2 (10-x)^2 = x^2 (100 - 20x + x^2) = x^4 - 20x^3 + 100x^2 = f(x)
Then
0=f'(x) = 4x^3 - 60x^2 + 200x
0 = x (4x^2 - 60x + 200)
= 4x( x^2 - 15x + 50)
= 4x( x - 10 )(x - 5 )
x = 0 , x = 10 , x = 5
so the extrema are (x=0, y=10)
(x=10, y = 0)
(x=5,y=5)
the min is 0 and the max is 625