Bradford T. answered 04/01/21
Retired Engineer / Upper level math instructor
f(x) = ln(x)
f(1) = 0 -> (1,0)
f'(x) = 1/x
f'(1) = 1
The slope m = 1.
y-y0 = m(x-x0)
y - 0 = 1(x-1)
y = x-1
y(.9) = .9-1 = -0.1
Actual ln(.9) ≈ -0.1054
Christian L.
asked 04/01/21Find the Linear approximation L(x) of the function f(x)=ln(x) at a=1 and use it to approximate Ln 0.9.
Bradford T. answered 04/01/21
Retired Engineer / Upper level math instructor
f(x) = ln(x)
f(1) = 0 -> (1,0)
f'(x) = 1/x
f'(1) = 1
The slope m = 1.
y-y0 = m(x-x0)
y - 0 = 1(x-1)
y = x-1
y(.9) = .9-1 = -0.1
Actual ln(.9) ≈ -0.1054
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LoLa M.
Could you help with the question I just uploaded?04/01/21