
Bradford T. answered 04/01/21
Tutor
4.9
(29)
Retired Engineer / Upper level math instructor
f(x) = ln(x)
f(1) = 0 -> (1,0)
f'(x) = 1/x
f'(1) = 1
The slope m = 1.
y-y0 = m(x-x0)
y - 0 = 1(x-1)
y = x-1
y(.9) = .9-1 = -0.1
Actual ln(.9) ≈ -0.1054
LoLa M.
Could you help with the question I just uploaded?04/01/21