Raymond B. answered 04/01/21
Math, microeconomics or criminal justice
h = sqr(b^2 + a^2), b=15, a=20, b'=-5, a'=-6
h' = [(1/2)/sqr(b^2+a^2)](2bb' + 2aa') = sqr(15^2+20^2)(15(-5)+20(-6)
= (-75-120)/sqr625 = (-195)/25 =-- 39/5 = - 7.8 inches per second
hypotenuse is decreasing at the rate of 7.8 inches per second
check the answer by looking at what happens in one second
short leg goes from 15 to 10
longer leg goes from 20 to 14
hypotenuse goes from 25 to 17.2
25-17.2 = 7.8 decrease in one second. That's -7.8 inches per second rate of change for the hypotenuse