We will use the limit definition of the derivative function to show this:
f'(x) = limh→0 [f(x+h) - f(x)] / h (This is a useful definition to memorize, btw.)
f(x) = 3 - x2
f'(x) = limh→0 [(3 - (x+h)2 - (3 - x2)] / h
= limh→0 [ 3 - x2 - 2xh - h2 - 3 + x2] / h
= limh→0 [ - 2xh - h2 ] / h
= limh→0 - 2x - h
= -2x
Notice that using this limit definition, we should always get the terms without an h in the numerator to cancel, leaving only terms with an h there. Then we can factor out h, cancel with the denominator, and then let h = 0 to determine the limit.
Philipe F.
Thank you very much, this helped greatly!03/31/21