Raymond B. answered 03/31/21
Math, microeconomics or criminal justice
Take the derivative of R-C and set equal to zero
(R-C)' = 1300 - 2x - 1100 = 0
2x =200
x = 200/2 = 100 units = profit maximizing output
Profit = R-C = 1300x -x^2 - 1100x -600
R(100)-C(100) = 1300(100) -(100)^2 -1100(100) -600
= 1300(100) -10000 -110000 -600
= 130,000 -10,000 - 110,000 -600
= $9,400 = maximum profit