Translate x = e(y-3) to y − 3 = ln |x| or y = ln |x| + 3 and translate x = √y to y = x2.
Use a graphing calculator to show the curves for y = ln |x| + 3 and y = x2. The
plot will show that the curve for y = x2 is to the right of the curve for y = ln |x| + 3
on the x-y plane.
Going back to x = e(y-3) and x = √y, one would then construct the integral sought
as ∫(√y − e(y-3))dy with the limits of integration computed as y = (0.5)2 or 0.25 and
y = (1.5)2 or 2.25.
The final expression would then be ∫(from y=0.25 to y=2.25)(√y − e(y-3))dy.
This would be (B) among the choices above.