This is a straight application of integration.
dy/dx = 12x2 + 10x + C1 ... since dy/dx = 0 when x=0, C1 =0
y= 4x3 + 5x2 + C2
y passes through (0,7) which makes C2 = 7.
Sophie M.
asked 03/30/21This is a straight application of integration.
dy/dx = 12x2 + 10x + C1 ... since dy/dx = 0 when x=0, C1 =0
y= 4x3 + 5x2 + C2
y passes through (0,7) which makes C2 = 7.
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