Mark M. answered 03/29/21
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = exg(x)
f(ln2) = eln2g(ln2) = 2g(ln2) = 4. So, g(ln2) = 2
f'(x) = exg(x) + exg'(x)
f'(ln2) = 2g(ln2) + 2g'(ln2) = 4 + 2g'(ln2) = 6. So, g'(ln2) = 1.