Yefim S. answered • 03/29/21
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IIxII = (12 + (-1/2)2 + (1/4)2 + (-1/8)2 + 1/16)2 + ... + (1/(-2)n-1)2 + ...)1/2 = [1/(1 - 1/4)]1/2 = (4/3)1/2 = 2/√3
Jaden S.
asked • 03/29/21Find the norm ∥x∥ of x=(1,−1/2,1/4,−1/8,1/16,…,1/((−2)^n−1),…) in ℓ2.
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