Mark M. answered 03/28/21
Mathematics Teacher - NCLB Highly Qualified
0.75 = Ce0k
0.75 = Ce
0.2759 ≈ C
3 = 0.2759e6k
10.8731 ≈ e6k
ln 10.8731 ≈ 6k
Can you solve for k and answer?
Amanda V.
or 0.5945323798?03/28/21
Amanda V.
asked 03/28/21Find the exponential function y = Ce^kt that passes through the two given points. (0, 3/4), (6, 3)
Mark M. answered 03/28/21
Mathematics Teacher - NCLB Highly Qualified
0.75 = Ce0k
0.75 = Ce
0.2759 ≈ C
3 = 0.2759e6k
10.8731 ≈ e6k
ln 10.8731 ≈ 6k
Can you solve for k and answer?
Amanda V.
or 0.5945323798?03/28/21
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Amanda V.
I feel like I am getting k wrong. I have -0.095903/28/21