Mark M. answered • 03/26/21
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = tan2(2x)
f'(x) = 2tan(2x) [ tan(2x)]' = 2tan(2x)sec2(2x)(2) = 4tan(2x)sec2(2x)
Tori P.
asked • 03/26/21Apply chain rule to find the derivatives of each of the function.
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2 Answers By Expert Tutors
4 tan 2x..(2 tan 2x) * 2
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Paul M.
03/29/21