This is a direct application of integration.
v (t) = ∫a(t) dt
and s(t) = ∫v(t) dt.
Use the initial conditions to determine the constants of integation.
John P.
asked 03/24/21A particle is moving along a line according to the equation of motion s = f(t) where s is in ft and t in seconds.
1) Given a = 2 t 2t − ; s = 1 when t = 0 and s = -3 when t = 2. Express v and s in terms of t.
This is a direct application of integration.
v (t) = ∫a(t) dt
and s(t) = ∫v(t) dt.
Use the initial conditions to determine the constants of integation.
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