other question not too confident

Question

Find the points at which y=f(x)=x9−2x has a global maximum and minimum on the interval 0≤x≤2.4Round your answers to two decimal places. 

Global Maximum: 

(x,y) = (_,_)

Global Minimum: 

(x,y) = (_,_)

Answer 1

You should graph this to see what happens!

There is no global max nor min...the function is unbounded whenever |x| gets large.

The local max is at x=-.8286 (approximately) and the local min is at x=.8286.

Note.8286 is approximately the 8th root of 2/9 which comes from the derivative set = 0.