Jsjsjdjdis D.

asked • 03/21/21

if f(x)=e^4x^2/x then what is the value of f'(-1)? Express your answer in simplest form with no negative exponents.

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Dayv O. answered • 03/22/21

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if f(x)=e^4x^2/x


then isn't f(x) a constant, f(x)=e8 for all x.

very much f' when f is constant is f' = 0 for all x.

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Dayv O.

perhaps you are asking if f(x)=e^((4x)^(2/x)) which is different than f(x)=(e^4x)6(2/x). then what is f'(-1). Let me know, sometimes I don't know which to choose from the two. Yikes for f(x)=e^((4x)^(2/x)) as I think it doesn't exist at x=-1.
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03/22/21

RAFAH A. answered • 03/22/21

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Dayv O.

Hi Rafah, it looks like nice calculus work. But I am pretty sure x^x is undefined for x<0. If f(x) doesn't exist x<0, how can there be f'(-1)?
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03/22/21

RAFAH A.

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Hi Dayv , Thanks for your comment, for this function the Domain has to be x>0, that is why I explained for the student how to solve such type of functions, and I did not calculate for f ' (-1) , because he has to figure out that it will be undefined , and that is cleared because we have ln x
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03/22/21

Dayv O.

great, thanks.
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03/22/21

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