if dy/dx= square root x, then the average rate of change of y with respect to x on the closed interval [0,4] is?

Answer 1

f'(x) = √x

f(x) = ∫f'(x)dx = (2/3)x^3/2 + C

AveRate = (f(4)-f(0))/(4-0) = (2/12)(4)^3/2 = 8/6 = 4/3